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9 November, 01:43

What minimum concentration of clâ is required to begin to precipitate pbcl2? for pbcl2, ksp=1.17Ã10â5?

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  1. 9 November, 04:59
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    Missing in your question : [Pb2+] = 0.085 M

    So from this balanced equation:

    PbCl2 ↔ Pb+2 + 2Cl-

    when Ksp = [Pb+2][Cl]^2

    when we have Ksp = 1.17x10^-5 & [Pb+2] = 0.085 M so by substitution:

    1.17x10^-5 = 0.085 [Cl-]^2

    ∴[Cl]^2 = (1.17x10^-5) / 0.085 = 1.38x10^-4

    ∴[Cl-] = √0.0002

    = 0.0117 M

    So 0.0117 M is the minimum concentration requires precipitating PbCl2
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