The buoyant force acting on a submerged object equals the weight of the fluid displaced by the object. What is the weight of the water displaced by a block of iron with the dimensions of 3.00 cm x 3.00 cm x 3.00 cm? The iron has a mass of 213 g. Remember that water has a density of 1.00 g/cm3. Hint: Determine the volume of the displaced water. Then determine the mass using your knowledge of the density of water. Finally, convert the mass to weight using Weight = mg, where mass is in kilograms and gravity, g = 9.80 m/s2.

27.0 g

2.76 g

265 N

0.265 N

The buoyant force acting on a submerged object equals the weight of the fluid displaced by the object. What is the weight of the water displaced by a block of iron with the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. It has a mass of 213 g. Remember that water has a density of 1.00 g/cm3.

To determine the weight of the displaced water, we need to know the volume of the block. Since the entire block is submerged, the volume of displaced water = volume of block!

Volume of block = 3 * 3 * 3 = 27 cubic cm

Now we need to determine the weight of 27 cc of water.

Weight = mass in kg * 9.8

Density = mass / volume

1 g/cc = mass / 27

Mass = 27 g

Weight = mass in kg * 9.8

Mass in kg = 0.027 kg

Weight of block = 0.027 * 9.8 = 0.2646 N

The buoyant force acting on a submerged object equals the weight of the fluid displaced by the object.

Buoyant force = 0.2646 N

a is incorrect, because force is weight, not mass

d is correct,