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4 August, 18:22

Which compound (s will not form a yellow precipitate when treated with excess iodine in the presence of naoh?

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  1. 4 August, 19:06
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    For example:

    5Cl₂ + I₂ + 12NaOH = 10NaCl + 2NaIO₃ + 6H₂O

    Na₂S₂O₃ + 4I₂ + 10NaOH = 8NaI + 2Na₂SO₄ + 5H₂O
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