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2 March, 06:03

Calculate the enthalpy change for the thermite reaction: 2al (s) + fe2o3 (s) →2fe (s) + al2o3 (s), δh∘rxn=-850 kj when 8.00 mol of al undergoes the reaction with a stoichiometrically equivalent amount of fe2o3. express your answer to three significant figures and include the appropriate units.

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  1. 2 March, 09:38
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    Enthalpy change for the balanced equation is - 850kj

    And from the balanced equation we come to know that for 2 moles of Al, the value is - 850kj

    for 1 mole of Al = - 850/2 = - 425 kj

    We have to find the enthalpy change for 8 moles of Al = 8 x - 425 = 3400kj

    Thus, the enthalpy change for 8 mol of Al is - 3400kj.
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