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17 August, 04:21

If a sample of barium contains 2.3 x 1023 atoms of barium, how many grams of barium are in the sample? A) 0.38 g. B) 2.62 g. C) 52.4 g. D) 359.5 g.

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  1. 17 August, 06:28
    0
    N = 2.3 * 10 ^23 atoms

    Avogadro constant: N a = 6.02 * 10 ^ 23

    n = N : N a = 2.3 * 10 ^23 : 6.02 * 10 ^23 = 0.381 mol

    m = n * M = 0.381 mol * 137 g/mol = 52.197 ≈ 52.4 g

    Answer: C) 52.4 g
  2. 17 August, 06:37
    0
    N = number of molecules

    n = 2.3x10^23/6.022x10^23

    = 0.381 mol

    Now,

    M = molar mass in g/mol

    m = mass in grams

    m=nxM

    =0.381 molx137 g/mol

    = 52.197g

    So, the correct answer should be C
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