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8 April, 23:21

What is the [OH-] in a solution with a pOH of 4.22?

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  1. 8 April, 23:37
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    We are asked what is the [OH-] in a solution with a POH of 4.22 and to solve this we need to use the equation written below:

    POH = - log [OH-]

    10^-poh=[OH-]

    10^-4.22=[OH-]

    6.03X10^-5 M = [OH-]

    The answer is 6.03x10^-5 M.
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