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8 June, 18:15

Calculate the ph of a 0.0075 m ca (oh) 2 solution.

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  1. 8 June, 19:41
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    Ca (OH) ₂ = Ca²⁺ + 2OH⁻

    [OH⁻]=2c{Ca (OH) ₂}

    pH=14+lg[OH⁻]

    pH=14+lg (2c{Ca (OH) ₂})

    pH=14+lg (2*0.0075) = 12.18
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