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23 March, 23:42

What is the total number of moles of nacl formed when 2 moles of na2cro4 react completely?

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Answers (2)
  1. 24 March, 00:28
    0
    The balanced chemical equation for the above reaction is as follows;

    2Na₂CrO₄ + 2HCl - - - > Na₂Cr₂O₇ + 2NaCl + H₂O

    stoichiometry of Na₂CrO₄ to NaCl is 2:2

    the amount of moles of Na₂CrO₄ reacted is equal to the number of moles of NaCl produced.

    We are told that Na₂CrO₄ reacts completely, this means that this is the limiting reactant, amount of product forms depends on amount of limiting reactant present.

    When 2 mol of Na₂CrO₄ is used up, according to stoichiometry number of NaCl moles formed are equal to that.

    Therefore number of NaCl moles formed - 2 mol
  2. 24 March, 00:30
    0
    Na2CrO4 react with PbCl2 to form PbcrO4 + 2 NaCl

    the total number of moles of nacl when 2 Na2crO4 react completely is calculated by use of reacting ration between Na2CrO4 and NaCl which is 1:2

    therefore the moles of Nacl is = 2 x2 = 4 moles
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