What mass of aluminum will be deposited on the cathode if an electric current of 0.15 a is run for 4 5s when a solution of al (no3) 3 is subjected to electrolysis?

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Chemistry

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14 September, 19:40

What mass of aluminum will be deposited on the cathode if an electric current of 0.15 a is run for 4 5s when a solution of al (no3) 3 is subjected to electrolysis?

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Houston Eaton · Answer 1

Mass of Al, m = ?

Molar mass of copper Al, M = 27.0 g/mol

time, t = 45 s

current, c = 0.15 A

valency of Al in Al (NO₃) ₃, z = + 3

From Faraday's 1st law,

m = Mct/zF

where F = Faraday constant = 96500 C/mol

Substitute all the values,

m = [ (27.0 g/mol) (0.15 A) (45 s) ] / [3] [96500 C/mol]

= 6.3 x 10⁻⁴ g

Mass of aluminium = 6.3 x 10⁻⁴ g

Therefore, mass of aluminium plated on electrode = 6.3 x 10⁻⁴ g