According to the following reaction, how many grams of sulfur are formed when 37.4 g of water are formed?

2H₂S (g) + SO₂ (g) → 3S (s) + 2H₂O (l)

We see that the molar ratio of sulfur to water is:

3 : 2

We first compute the moles of water:

moles = mass / Mr

moles = 37.4 / 18

moles = 2.08

By the ratio, moles of sulfur:

3.12

Mr sulfur = 64

mass = 3.12 x 64

mass = 199.7 grams