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12 July, 15:49

If 40.0 g of water at 70.0°c is mixed with 40.0 g of ethanol at 10.0°c, what is the final temperature of the mixture?

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  1. 12 July, 19:32
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    When the heat lost by water = heat gained by ethanol

    ∴ (M * C * ΔT) w = (M*C*ΔT) eth

    when Mw mass of water = 40 g

    C specific heat of water = 4.18

    ΔT = (70 - Tf)

    and M (eth) mass (ethanol) = 40 g

    C specific heat of ethanol = 2.44

    ΔT = (Tf - 10)

    by substitution:

    40 * 4.18 * (70 - Tf) = 40 * 2.44 * (Tf-10)

    ∴Tf = 47.9 °C
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