If a gas occupies 240 mL at 800.0 mmHg and the pressure is increased to 1200.0 mmHg, what will be the new volume of the gas? assume the temperature remains constant. A) 45 mL B) 95 mL C) 160 mL D) 360 mL

Question

Chemistry

Tabby

4 September, 20:18

If a gas occupies 240 mL at 800.0 mmHg and the pressure is increased to 1200.0 mmHg, what will be the new volume of the gas? assume the temperature remains constant. A) 45 mL B) 95 mL C) 160 mL D) 360 mL

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Answers (2)

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Jayvion Yates · Answer 1

V2 = V1 x P1/P2 = 240mL x 800.0mmHg / 1200.0mmHg = 160 ml

Geovanni Reid · Answer 2

Boyle studied the relation between the volume and the pressure of the gas at constant temperature.

Boyle's law states that: " At constant temperature, the volume of a given mass of gas is inversely proportional to its pressure"

This means that:

PV = constant

This can also be written as:

P1V1 = P2V2 where:

P1 is the initial pressure = 800 mmHg

V1 is the initial volume = 240 ml

P2 is the final pressure = 1200 mmHg

V2 is the final volume that we need to calculate

Substitute with the givens in the above relation to get the value of the volume as follows:

(800) (240) = (1200) (v2)

192000 = 1200 (V2)

V2 = 192000 / 1200

V2 = 160 ml