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18 December, 13:29

What is the hydronium ion concentration of a 0.500 m acetic acid solution with ka = 1.8 * 10-5? the equation for the dissociation of acetic acid is:?

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  1. 18 December, 13:39
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    The equation for the dissociation of acetic acid is:

    CH3CO2H (aq) + H2O (l) H3O + (aq) + CH3CO2 - (aq)

    pH = 0.5 (4.74 - lg (0.5)) = 2.52

    so

    [H^+] = 3.02*10^-3 M = 3.02 mM
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