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4 September, 20:29

What is the molarity of a solution that contains 2.35 g of nh3 in 0.0500 l of solution?

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  1. 4 September, 21:17
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    The molarity is the number of moles in 1 L of the solution.

    The mass of NH₃ given - 2.35 g

    Molar mass of NH₃ - 17 g/mol

    The number of NH₃ moles in 2.35 g - 2.35 g / 17 g/mol = 0.138 mol

    The number of moles in 0.05 L solution - 0.138 mol

    Therefore number of moles in 1 L - 0.138 mol / 0.05 L x 1L = 2.76 mol

    Therefore molarity of NH₃ - 2.76 M
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