Complete the balanced overall ionic equation for lead (ii) nitrate dissolving in water. $$pb (no3 ) 2 (s)

Missing question: What will happen if we combine the solution of sodium iodide and the solution of lead (II) nitrate?

Chemical reaction 1: Pb (NO ₃) ₂ (s) → Pb²⁺ (aq) + 2NO₃⁻ (aq).

Chemical reaction 2: 2NaI (aq) + Pb (NO₃) ₂ (aq) → PbI₂ (s) + 2NaNO₃ (aq).

Ionic reaction:

2Na⁺ (aq) + 2I⁻ (aq) + Pb²⁺ (aq) + 2NO₃⁻ (aq) → PbI₂ (s) + 2Na⁺ (aq) + 2NO₃⁻ (aq).

Net ionic reaction: 2I⁻ (aq) + Pb²⁺ (aq) → PbI₂ (s).