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17 October, 08:13

How many liters of a 0.880 m solution can be made by adding 25.5 g of lithium fluoride?

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  1. 17 October, 10:29
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    Molarity can be defined as the number of moles of solute in volume of 1 L solution

    molarity of LiF is 0.880 M

    the mass of LiF added is 25.5 g / 26 g/mol = 0.98 mol

    the concentration of LiF that is to be prepared = 0.880 M

    volume of 0.880 mol is 1 L

    therefore volume that contains 0.98 mol - 0.98 mol / 0.880 mol/L

    Volume of solution containing 25.5 g of LiF is - 1.11 L

    therefore volume required is - 1.11 L
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