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20 December, 11:36

Two 20.0-g ice cubes at - 20.0 °c are placed into 205 g of water at 25.0 °c. assuming no energy is transferred to or from the surroundings, calculate the final temperature, tf, of the water after all the ice melts.

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  1. 20 December, 14:21
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    Taking in account that ice cubes are made with water, both substance has the same heat propieties, so then only needs to consider mass and temperatures to reach a solution and use a weighted average of the initial temperatures, 2 ice of 20 gr. at - 20ºC or 253.15º K and 205 gr of water at 25ºC or 298.15ºK, then final temperature, Tf is: Tf = ((2*20*253.15) + (205*298.15)) / (2*20+205) = 290.8ºK or 17.65ºC The final temperature after ice melts decrease till 17.65ºC
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