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Chemistry
Kamila
3 April, 07:12
Calculate the ph of 0.63 m nh3 (kb=1.8*10-5).
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Zayden Carr
3 April, 09:29
0
[OH-] = √1.8*10^-5 * 0.15
[OH-] = 1.64*10^-3M
pOH = - log (1.64*10^-3)
pOH = 2.79
pH = 14 - 2.79
pH = 11.21
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