Ask Question
25 January, 09:48

Determine the percent yield for the reaction between 3.74 g of na and excess o2 if 5.34 g of na2o2 is recovered.

+3
Answers (1)
  1. 25 January, 10:09
    0
    Answer is: the percent yield for the reaction is 84,2%.

    Chemical reaction: 2Na + O₂ → Na₂O₂.

    m (Na) = 3,74 g.

    n (Na) = m (Na) : M (Na).

    n (Na) = 3,74 g : 23 g/mol.

    n (Na) = 0,162 mol.

    From chemical reaction: n (Na) : n (Na₂O₂) = 2 : 1.

    n (Na₂O₂) = 0,162 mol : 2 = 0,081 mol.

    m (Na₂O₂) = 0,081 mol · 78 g/mol.

    m (Na₂O₂) = 6,341 g.

    yield of reaction = 5,34 g / 6,341 g · 100%.

    yield of reaction = 84,2%.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Determine the percent yield for the reaction between 3.74 g of na and excess o2 if 5.34 g of na2o2 is recovered. ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers