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Chemistry
Leland
17 July, 13:18
Compare the rates of effusion of nh3 and o2
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Ralph Juarez
17 July, 14:34
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According the Graham's Law of effusion, if we let M₁ and R₁ be the mass and effusion rate of NH₃ and M₂ and R₂ be the mass and effusion rate of O₂, then:
R₂/R₁ = √ (M₁/M₂).
Since M₁ = 14.01 + 3*1.01 = 17.04 and M₂ = 16 * 2 = 32, we see that:
R₂/R₁ = √ (17.04/32) = 0.73
==> R₂ = 0.73 * R₁.
Thus, O₂ effuses at 73% the speed that NH₃ does
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