What is the mass of nickel (ii) nitrate (182.71 g/mol) dissolved in 25.0 ml of 0.100 m ni (no3) 2 solution?

The mass of ni (NO3) 2 that dissolved in 25.0 ml of 0.100m ni (NO3) 2 solution is calculated as follows

fin the number of moles = molarity x volume in liters

=25 x0.100 / 1000 = 2.5 x10^-3 moles

mass = mass x molar mass

= 2.5 x10^-3 moles x 182.71 g/mol = 0.457 grams