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4 September, 07:01

B2O3 (s) + 3C (s) + 3Cl2 (g) - - - > 2 BCl3 (g) + 3CO (g)

Calculate how many moles of BCl3 are produced from the reaction of 61.0g of B203?

A. 1.75 mol

B. 0.0150 mol

C. 51.3 mol

D. 211 mol

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Answers (1)
  1. 4 September, 09:44
    0
    C. 51.3 mol is the answer
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