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15 August, 20:07

If δh = - 70.0 kj and δs = - 0.400 kj/k, the reaction is spontaneous below a certain temperature. calculate that temperature.

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  1. 15 August, 22:33
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    According to this formula, when:

    ΔG = ΔH - T*ΔS

    when the reaction is thermodynamically spontaneous ΔG < 0

    ∴ ΔH - T * ΔS = 0

    ∴T*ΔS = ΔH

    ∴ T = ΔH / ΔS

    when we have:

    ΔH = - 70KJ

    and ΔS = - 0.4 KJ/K

    So by substitution:

    T = - 70KJ / - 0.4

    = 175 K

    ∴the certain temperature below which the reaction will be thermodynamically spontaneous is 175 K
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