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17 December, 20:38

How many lone pairs of electrons are represented in the Lewis structure of a phosphate ion (PO43-) ? 10 12 21 24

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  1. 17 December, 23:59
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    To illustrate the Lewis structure,

    P has 5 valence electrons

    O has 6 valence electrons (each for 4 oxygen)

    And finally, for every negative charge, there is an additional valence electron

    We should add these all up = 5 + 24 + 3 = 32 valence electrons

    With this, we can be guided to illustrate the lewis structure as P as central atom and the 3 oxygen each with a single bond with P and 1 oxygen with a double bond with P. We place the valence electrons until octet rule is satisfied,

    we will be left with 12 lone pairs for phosphate ion.
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