How many molecules are present in 1296 g of dinitrogen pentoxide (N2O5) ?

1.199 * 1024

7.2269 * 1025

7.2269 * 1024

1.199 * 1023

7.2269 * 1023

Solve for the molecules present in 1296 g of dinitrogen pentoxide (N2O5)

The molar mass of N2O5 is 108 g/mol.

1296g of N2O5 has 1296 / 108 = 12 moles.

1 mole contains 6.022 x 10^23 molecules.

6.022 x 10^23 x 12 = 7.226 x 10^24

Therefore, there are 7.226 septillion (7.226 x 10^24) molecules in 1296g of dinitrogen pentoxide.