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29 December, 03:24

What is the molarity of NaOH, if 15g of NaOH is mixed with 600mL?

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  1. 29 December, 04:20
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    M (NaOH) = 15 g

    v=600 ml=0.6 l

    n (NaOH) = m (NaOH) / M (NaOH)

    C=n (NaOH) / v=m (NaOH) / [M (NaOH) v]

    C=15g/[40g/mol*0.6 l]=0.625 mol/l

    0.625M

    [H⁺]=7.5*10⁻²

    pOH=14-pH=14+lg[H⁺]

    pOH=14+lg (7.5*10⁻²) = 14-1.125=12.875
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