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22 March, 07:17

A compound is found to contain 38.65 % carbon, 16.25 % hydrogen, and 45.09 % nitrogen by mass. what is the empirical formula for this compound?

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  1. 22 March, 09:53
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    The molar mass of carbon is 12, hydrogen is 1, and nitrogen is 14, hence the ratio are:

    C = 38.65 / 12 = 3.22

    H = 16.25 / 1 = 16.25

    N = 45.09 / 14 = 3.22

    Divide the three by the lowest ratio which is 3.22:

    C = 3.22 / 3.22 = 1

    H = 16.25 / 3.22 = 5

    N = 3.22 / 3.22 = 1

    So the empirical formula is:

    CHN
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