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20 April, 02:36

How much of 90% ethanol must be mixed with 10% ethanol to make 1 pint of a 40% ethanol solution?

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  1. 20 April, 03:21
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    Amount of 90% Ethanol=0.375 pint

    Amount of 10% Ethanol=0.625 pint

    Because:

    90x+10y=40

    x+y=1

    x=1-y

    90 (1-y) + 10y=40

    90-90y+10y=40

    90-80y=40

    80y=50

    y=5/8

    x=1-5/8=3/8
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