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23 April, 19:18

if i have 7.7 moles of a gas at a pressure of 0.09 ATM and a temperature of 329 K, what is the volume of the container that the gas is in?

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  1. 23 April, 22:19
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    N=number of moles=7.7 moles.

    P=pressure at atm=0.09 atm

    T=temperature at ºK=329 ºK

    R=universal gas costant=0.082 (L*atm) / (ºK*mol)

    The ideal gas law:

    PV=nRT

    therefore:

    0.09 atm*V=7.7 moles * 0.082 (L*atn) / (ºK * mol) * 329ºK

    V = (7.7 moles * 0.082 (L*atn) / (ºK * mol) * 329ºK) / (0.09 atm) = 2,308.12 L

    Answer: the volume is 2,308.12 litres
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