How many grams of water are produced from the reaction of 40.3 g of oxygen according to this equation? 2h2 (g) + o2 (g) → 2h2o (g) ?

The balanced equation for the above reaction is as follows;

2H₂ + O₂ - - > 2H₂O

stoichiometry of O₂ to H₂O is 1:2

number of O₂ moles reacted - 40.3 g / 32 g/mol = 1.26 mol

according to molar ratio

number of water moles produced = 2 x number of O₂ moles reacted

number of water moles formed - 1.26 x 2 = 2.52 mol

mass of water produced = 2.52 mol x 18 g/mol = 45.4 g

45.4 g of water produced