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28 January, 21:04

How long will it take for 90% of the ch3cn to convert to ch3nc?

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  1. 28 January, 22:43
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    A (t) = A (o) (½) ^t/h

    A (t) / Ao = 0.5^t/h

    Where A (t) = amount present, A (o) = initial amount, t = elapsed time, h = half-life

    If 95% has been converted then At/Ao = 0.06 t½ = 15.0 h

    log (0.06) = log (0.5) t/15

    15*log (0.05) / log (0.5) = t

    t = 60.9 h
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