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19 July, 03:47

What is the [OH-] in a solution of ph 3.00?

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  1. 19 July, 05:51
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    PH = 3, pOH = 14-3 = 11

    [OH-] = 10^ (-pOH) = 10^ (-11) = 1E-11 or 1*10^-11
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