Ask Question
26 October, 18:24

For the reaction cl2 + 2kbr → 2kcl + br2, how many moles of potassium chloride are produced from 331.1 g of potassium bromide?

+5
Answers (1)
  1. 26 October, 20:39
    0
    Equation is as follow,

    Cl ₂ + 2 KBr → 2 KCl + Br ₂

    According to equation,

    238 g (2 moles) KBr produced = 2 Moles of KCl

    So,

    331.1 g of KBr will produce = X moles of KCl

    Solving for X,

    X = (331.1 g * 2 mol) : 238 g

    X = 2.78 Moles of KCl

    Result:

    331.1 g of KBr produces 2.78 Moles of KCl.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “For the reaction cl2 + 2kbr → 2kcl + br2, how many moles of potassium chloride are produced from 331.1 g of potassium bromide? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers