90.0 g of Ca (NO3) 2 was used to create a 2.6 M solution. What is the volume of the solution? (Ca (NO3) 2 = 164.0878 g/mol)

The concentration of a solution is:

concentration = moles / volume (dm³)

The moles of calcium nitrate:

moles = mass / Mr

moles = 90 / 164.0878

moles = 0.55

2.6 = 0.55 / volume

Volume = 0.211 dm³

Volume = 211 cm³