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15 March, 20:27

If 155 grams of potassium (K) reacts with 122 grams of potassium nitrate (KNO3), what is the limiting reagent?

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  1. 15 March, 22:16
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    K:

    m=155g

    M=39g/mol

    n = 155g / 39g/mol ≈ 3,97mol

    KNO₃:

    m=122g

    M=101g/mol

    n = 122g/101g/mol = 1,21mol

    2K + 10KNO₃ ⇒ 6K₂O + N₂

    2mol : 10mol

    3,97mol : 1,21mol

    limiting reagent

    KNO₃ is limiting reagent
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