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17 September, 17:27

When hydrogen burns, water vapor is produced. the equation is 2h2 (g) + o2 (g) → 2h2o (g). if 12 l of oxygen are consumed at stp, what volume of water vapor is produced?

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  1. 17 September, 20:11
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    The volume of water vapor produced if 12 l of oxygen are consumed at STP is calculated as follows

    2H2 (g) + O2 (g) = 2H2O

    by use of mole ratio between O2 to H2O which is 1:2 the number of liters of H2O produced is therefore

    = 2/1 x12 L = 24 L
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