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7 July, 20:59

The reaction for the combustion of benzene is: 2C6H6 + 15O2 → 12 CO2 + 6 H2O. How moles of O2 are required to produce 130 g CO2 in the presence of excess C6H6?

a. 2.36

b. 2.95

c. 3.69

d. 5.80

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Answers (1)
  1. 7 July, 22:19
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    2 C ₆ H ₆ + 15 O ₂ → 12 CO ₂ + 6 H ₂ O

    if mass of CO ₂ = 130g

    since moles = mass : molar mass

    then moles of CO₂ = 130 g : ((12 * 1) + (16 * 2))

    = 2.9545 mol

    Mole ratio of CO₂ : O₂ is 12 : 15

    ∴ if mole of CO₂ = 2.9545 mol

    then moles of O₂ = (2.9545 : 12) * 15

    = 3.6931 mol

    ∴ the answer is Option C
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