If 14g of ethene reacts with excess amount of steam to give 17.25g of ethanol what is the percentage yield

Molecular wt if ethene = 28 g/mol

take 14 : 28 = 0.5 mol

since there is a 1:1 ratio between ethene and ethanol one should produce 0.5 mol

MW ethanol = 46

0.5 * 46 = 23 g should be produced.

17.25/23 = 0.75 = 75% Percent yield