The molar heats of fusion and sublimation of lead are 4.77 and 182.8 kj/mol, respectively. estimate the molar heat of vaporization of molten lead.

The molar heat of vaporization of molten lead is the amount of heat that is required for one mole of lead to be evaporated. The concept is also similar to heat of sublimation. Therefore, the answer should be 182.8 kJ. Each mole of molten lead needs 182.8 kJ to vaporize.