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27 November, 04:57

If a gas at 740 mm Hg and 70c has its pressure lower to 720 mm Hg, what will it's temperature be if volume is held consistent

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  1. 27 November, 06:48
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    When the volume and quantity of the gas are held constant, we can use the Gay-Lussac's Gas Law expressed as

    P1/T1 = P2/T2

    in which if the pressure of the gas decreases, we know that the temperature decreases.

    We first convert the temperature to absolute temperature

    T1 = 70 + 273 = 343 K

    Rearranging the Gay-Lussac's equation to solve for the final temperature

    T2 = P2T1 / P1

    = (720 mmHg) (343 K) / 740 mmHg

    = 334 K = 61ºC
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