How much heat is absorbed by 15.5 g of water when its temperature is increased from 20.0°C to 50.0°C? The specific heat of water is 4.184 J

The amount of heat that needs to be absorbed by a certain mass of water is calculated through the equation,

H = mcpdT

where m is mass, cp is specific heat, and dT is temperature difference.

H = (15.5 g) (4.184 J/g°C) (50°C - 20°C)

H = 1945.56 J

Thus, the amount of heat that needs to be absorbed is 1945.56 J.