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28 November, 20:14

The solubility product constant of pbcl2 is 1.7 * 10-5. what is the maximum concentration of pb2 + that can be in ocean water that contains 0.0500 m nacl?

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  1. 28 November, 23:49
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    Answer is: the maximum concentration of Pb²⁺ is 6.8·10⁻³ M.

    Chemical reaction 1: PbCl₂ (s) → Pb²⁺ (aq) + 2Cl⁻ (aq).

    Chemical reaction 2: NaCl (aq) → Na⁺ (aq) + Cl⁻ (aq).

    Ksp (PbCl₂) = 1.7·10⁻⁵.

    c (NaCl) = c (Cl⁻) = 0.0500 M.

    Ksp (PbCl₂) = c (Pb²⁺) · c (Cl⁻) ².

    c (Pb²⁺) = Ksp (PbCl₂) : c (Cl⁻) ².

    c (Pb²⁺) = 1.7·10⁻⁵ M³ : (0.0500 M) ².

    c (Pb²⁺) = 0.000017 M³ : 0.0025 M².

    c (Pb²⁺) = 0.0068 M = 6.8·10⁻³ M.
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