How many moles of PbCl4 are needed to produce 2.00 g of Cl ions?

Question

Chemistry

Karly Galvan

8 February, 17:07

How many moles of PbCl4 are needed to produce 2.00 g of Cl ions?

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Fernanda · Answer 1

Answer is: 0,014 moles of PbCl₄ are needed.

Chemical dissociation: PbCl₄ → Pb⁴⁺ + 4Cl⁻.

m (Cl⁻) = 2,00 g.

n (Cl⁻) = m (Cl⁻) : M (Cl⁻).

n (Cl⁻) = 2 g : 35,45 g/mol.

n (Cl⁻) = 0,056 mol.

From chemical reaction: n (Cl⁻) : n (PbCl₄) = 4 : 1.

n (PbCl₄) = 0,056 mol : 4.

n (PbCl₄) = 0,014 mol = 1,4·10⁻² mol.