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5 January, 14:00

At 10°c one volume of water dissolves 3.10 volumes of chlorine gas at 1.00 atm pressure. what is the henry's law constant of cl2 in water? (r = 0.0821 atm • l • mol-1• k-1)

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  1. 5 January, 14:49
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    Answer is: 0,133 mol / l· atm.

    T (chlorine) = 10°C = 283K.

    p (chlorine) = 1 atm.

    V (chlorine) = 3,10 l.

    R - gas constant, R = 0.0821 atm·l/mol·K.

    Ideal gas law: p·V = n·R·T

    n (chlorine) = p·V : R·T.

    n (chlorine) = 1atm · 3,10l : 0,0821 atm·l/mol·K · 283K = 0,133mol.

    Henry's law: c = p·k.

    k - Henry's law constant.

    c - solubility of a gas at a fixed temperature in a particular solvent.

    c = 0,133 mol/l.

    k = 0,133 mol/l : 1 atm = 0,133 mol / l· atm.
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