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7 September, 12:34

An aqueous solution of glycerol, c3h8o3, is 48.0% glycerol by mass and has a density of 1.120 g ml-1. calculate the molality of the glycerol solution.

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  1. 7 September, 13:32
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    Answer is: the molality of the glycerol solution is 10.03 m.

    V (solution) = 100 mL.

    m (solution) = V (solution) · d (solution).

    m (solution) = 100 mL ·1.120 g/mL.

    m (solution) = 112 g.

    m (glycerol) = ω (glycerol) · m (solution).

    m (glycerol) = 0.48 · 112 g.

    m (glycerol) = 53.76 g.

    m (water) = 112 g - 53.76 g.

    m (water) = 58.24 g : 1000 g/kg = 0.05824 kg.

    n (C₃H₈O₃) = m (C₃H₈O₃) : M (C₃H₈O₃).

    n (C₃H₈O₃) = 53.76 g : 92 g/mol.

    n (C₃H₈O₃) = 0.584 mol.

    b (C₃H₈O₃) = n (C₃H₈O₃) : m (H₂O).

    b (C₃H₈O₃) = 0.584 mol : 0.05824 kg.

    m (C₃H₈O₃) = 10.027 mol/kg.
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