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28 July, 15:11

Calculate the pOH of a 9.03x10-5 M solution of NaOH.

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  1. 28 July, 18:34
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    NaOH - - - > Na⁺ + OH⁻

    1 mol 1 mol

    9.03x10⁻⁵ M 9.03x10⁻⁵ M

    pOH = - log[OH⁻]

    pOH = - log (9.03x10⁻⁵) = 4.04

    pOH=4.04
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