Consider the following methods:

public static void printSport (double n) {

System. out. print ("football ");

printSport ((int) (n));

}

public static void printSport (int n) {

System. out. print ("basketball ");

}

What is output by the method call printSport (8) ?

1. football

2. basketball

3. football basketball

4. football football basketball basketball

5. basketball football

Question

Computers & Technology

Tater Tot

2 July, 06:10

Consider the following methods:

public static void printSport (double n) {

System. out. print ("football ");

printSport ((int) (n));

}

public static void printSport (int n) {

System. out. print ("basketball ");

}

What is output by the method call printSport (8) ?

1. football

2. basketball

3. football basketball

4. football football basketball basketball

5. basketball football

+1

Answers (1)

Know the Answer?

Vinnie · Answer 1

2. basketball This is a classic case of overloading in C++. You have 2 functions, both named "printSport", but one of the functions receives an input of type double, and the other receives an input of type int. The specified method call passes a parameter of type int, so the version of printSport is called that receives a parameter of type int. And that version of printSport only prints the word "basketball". The other version of printSport is never called at all.