A circuit is supplied with 30 VDC and contains three resistors connected in series. The value or R1 is 80, the value of R2 is 1,000, and the value of R3 is 4,200. What is the voltage drop across R2?

The answer is 5.68 Volts.

So givens are electric supply of 30 VDC and the values of 3 resistors.

Given:

E = 30 VDC

R1 = 80 Ohms

R2 = 1000 Ohms

R3 = 42000 Ohms

And what we are looking for is the voltage on the second resistor.

First we have to get the current of the circuit.

I = E / (R1+R2+R3)

I = 30 / (80+1000+4200)

I = 30 / (5280)

I = 0.00568 A

Then get the voltage V = I x R

V = 0.00568 x 1000

V = 5.68 V