If you enter 1 2 3 in three separate lines, when you run this program, what will be displayed? print ("Enter three numbers: ") number1 = eval (input ()) number2 = eval (input ()) number3 = eval (input ()) # Compute average average = (number1 + number2 + number3) / 3 # Display result print (average)

If you enter (1 2 3)

The program takes the first input and call it number1=1

The program takes the second input and call it number2=2

The program takes the third input and call it number3=3

Then the program is meant to add number1 to number2 and to number3

Number1+number2+number3=1+2+3=6

After that the programs take the average of this number by dividing it by 3

I. e

Average = (Number1+number2+number3) / 3

Average = 6/3

Average = 2

The program will display the result average as "2"