Two buses leave school moving in opposite directions. after 15 minutes, they are both 10 miles away from the school. which statements correctly describe the motion of the buses?

the velocity of the buses is equal.

the average speed of the buses is equal.

the average speed of the buses is not equal.

the velocity of the buses is not equal.

both buses move with constant velocity the entire trip

its multiple choice answer. (its not really computer and tech its science but its not on there)

The correct answer is B. The average speed of the buses is equal.

Explanation:

Both buses have traveled the same distance after fifteen minutes, but this does not mean that their speed has been constant because they have had to face different traffic, traffic lights and roads. Even one of them may have had to stop longer than the other, but then it has compensated for that time stopped with greater speed, if traffic conditions allowed. Finally, both have traveled ten miles in fifteen minutes, which means that their average speed is the same.

The statements correctly describing the scenario are:

Both the buses move with same average speed. Velocity of buses is not equal.

Explanation:

As both the buses left the school at the same time and covered same distance in the same time but in opposite direction, velocity of buses is not equal.

Velocity has a particular direction, which in this case is opposite, so velocity can't be equal. Now the buses have been driven for the same time and distance with unequal velocities which implies both of them have same average speed.